IBM Placement Paper II

IBM Placement Paper & Interview 2010 @ Mysore

1.First is the Wrtten Test

2.GD

3.Technical Interveiw

4.HR

The process is very simple ibm peoples are very supportive . RS agarwal is good to study for written round
i am an electronics and communication students basics off c and C++ is must don get afraid only basics is enough even i don’t know how to write  programs. be confident have faith in god…
The pattern was
SECTION-1 [  matrix test] 15 question – 13 min.[ No negative marks for this section]
SECTION-2  [ Number series test]  20 question  4 min. 15 mins mathematical[Negative marking(1/4) is there for this section.]
SECTION-3[Analytical type(Apti)]12 question 15 min.[ Negative marking(1/4) is there for this
section.]
1.WRITTEN TEST: 
This is the new pattern of IBM. this new pattern has been implemented. it contains 3 sections.

SECTION 1, 

some information is given in the form of matrices, with headings for rows as row1,row2 …. Etc.For columns with headings
as column1,column 2…. Etc.those matrices r as follows.
Column1           column2           column3           column4
Row1                   @                    *                         2                      Z
Row2                    S                      K                      ?                      $
Row3                    I                       P                       Z                      +
Row4                    #                      8                       F                      Q

IBM Placement Paper I

IBM Placement Paper 2010 @ Hyderabad

Aptitude Test:

1. In 1978, a kg of paper was sold at Rs25/-. If the paper rate increases at 1.5% more than the inflation rate which is 6.5% a year, then what will be the cost of a kg of paper after 2 years?
(a) 29.12
(b) 29.72
(c) 30.12
(d) 32.65
(e) none of these
 

2. In A,B,C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A,B,and C have equal number of marbles.
(i) If x,y,z are the marbles initially with A,B,C respectively. Then the number of marbles B have at the end
(a) 2(x-y-z)
(b) 4(x-y-z)
(c) 2(3y-x-z)
(d) x + y-z
Ans. (c)
(ii) If the total number of marbles are 72, then the number of marbles with A at the starting
(a) 20
(b) 30
(c) 32
(d) 39
Ans. (d)